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8x^2-30+43x=0
a = 8; b = 43; c = -30;
Δ = b2-4ac
Δ = 432-4·8·(-30)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-53}{2*8}=\frac{-96}{16} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+53}{2*8}=\frac{10}{16} =5/8 $
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